the K-shell binding energy of an electron in a lead atom is 88.0 keV and the L-shell energy is approximately 15.0 keV. A 100 keV photon ejects a K-shell electron.a) what is the energy of the photoelectron?b)an L-shell electron makes a transition to fill the K-shell vacancy. what is the energy of the photon emitted in this process?
Solution:a)Energy of photoelectron = 100 -88 =12KeVb)E=R[ – Here R =Rydberg constantn for K shell = 1n for L shell = 2 = 10.97 10.97 = 7.5 J